Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - Chapter 1 Test Prep - Review Exercises - Page 175: 4


$\dfrac {11\left( k+p\right) }{10-a}$

Work Step by Step

$9x-11\left( k+p\right) =x\left( a-1\right) \Rightarrow x\left( 9-\left( a-1\right) \right) =11\left( k+p\right) \Rightarrow $ $x\left( 10-a\right) =11\left( k+p\right) \Rightarrow $ $x=\dfrac {11\left( k+p\right) }{10-a}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.