Answer
$\dfrac {11\left( k+p\right) }{10-a}$
Work Step by Step
$9x-11\left( k+p\right) =x\left( a-1\right) \Rightarrow x\left( 9-\left( a-1\right) \right) =11\left( k+p\right) \Rightarrow $
$x\left( 10-a\right) =11\left( k+p\right) \Rightarrow $
$x=\dfrac {11\left( k+p\right) }{10-a}$
