Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.6 Other Types of Equations and Applications - 1.6 Exercises - Page 147: 40

Answer

$16\ hrs$

Work Step by Step

Step 1. Use the table given in the exercise, the part of job completed by the faster pipe would be $12(\frac{1}{x})$, while the part of job completed by the slower pipe would be $12(\frac{1}{3x})$ Step 2. Together, the total parts should be 1, we have $12(\frac{1}{x})+12(\frac{1}{3x})=1$ or $\frac{1}{x}+\frac{1}{3x}=\frac{1}{12}$ Step 3. Solve the above equation: $\frac{4}{3x}=\frac{1}{12}$, thus $x=16\ hrs$
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