## Precalculus (6th Edition)

The solution is $x=-10$
$\dfrac{2x+5}{2}-\dfrac{3x}{x-2}=x$ Multiply the whole equation by $2(x-2)$: $2(x-2)\Big(\dfrac{2x+5}{2}-\dfrac{3x}{x-2}=x\Big)$ $(2x+5)(x-2)-3x(2)=2x(x-2)$ Evaluate the products indicated and simplify the equation: $2x^{2}+x-10-6x=2x^{2}-4x$ $2x^{2}+x-10-6x-2x^{2}+4x=0$ $-x-10=0$ Solve for $x$: $-x=10$ $x=-10$