Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.6 Other Types of Equations and Applications - 1.6 Exercises - Page 146: 17


The solution is $x=-10$

Work Step by Step

$\dfrac{2x+5}{2}-\dfrac{3x}{x-2}=x$ Multiply the whole equation by $2(x-2)$: $2(x-2)\Big(\dfrac{2x+5}{2}-\dfrac{3x}{x-2}=x\Big)$ $(2x+5)(x-2)-3x(2)=2x(x-2)$ Evaluate the products indicated and simplify the equation: $2x^{2}+x-10-6x=2x^{2}-4x$ $2x^{2}+x-10-6x-2x^{2}+4x=0$ $-x-10=0$ Solve for $x$: $-x=10$ $x=-10$
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