## Precalculus (6th Edition)

The solution to the given given equation cannot be $-\dfrac{2}{3}$ or $6$.
RECALL: The denominator of a rational expression is not allowed to be equal to zero. To find the numbers that will make the denominator equal to zero, equate each denominator to zero then solve each equation to obtain: \begin{array}{ccc} &2x+3=0 &\text{or} &x-6=0 \\&2x=-3 &\text{} &x=6 \\&x=-\frac{3}{2} &\text{} &x=6 \end{array} Thus, numbers $\left\{-\dfrac{3}{2}, 6\right\}$ are not possible solutions to the given equation. Therefore, the the solution to the given given equation cannot be $-\dfrac{2}{3}$ or $6$.