Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.5 Applications and Modeling with Quadratic Equations - 1.5 Exercises: 2

Answer

$\sqrt {r^{2}+ s^{2}}$

Work Step by Step

The length $(r)$ and width $(s)$ of the rectangle forms a right-angled triangle with the diagonal of the rectangle. In this triangle, the diagonal forms the hypotenuse. From the Pythagoras theorem, we know that $\sqrt {a^{2}+b^{2}}$ $=$ $c$ Substituting r and s into the formula, we get $\sqrt {r^{2}+ s^{2}}$ $=$ $D$ Where, $r$ $=$ Length of rectangle $s$ $=$ Breadth of rectangle $D$ $=$ Diagonal
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