Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.5 Applications and Modeling with Quadratic Equations - 1.5 Exercises - Page 128: 1



Work Step by Step

The length of the parking lot is given as $2x+200$ and the width is given as $ x$. The total area is $40,000 yd^{2}$. We know that the area of a rectangle is given by the product of length and breadth. ie, $l\times b = $ Area of rectangle Substituting the value of the length $(2x+200)$ and width $x$, we get $x\times(2x+200)=40,000$ Or, $x(2x+200)=40,000$ Which is option A.
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