## Precalculus (6th Edition)

$x(2x+200)=40,000$
The length of the parking lot is given as $2x+200$ and the width is given as $x$. The total area is $40,000 yd^{2}$. We know that the area of a rectangle is given by the product of length and breadth. ie, $l\times b =$ Area of rectangle Substituting the value of the length $(2x+200)$ and width $x$, we get $x\times(2x+200)=40,000$ Or, $x(2x+200)=40,000$ Which is option A.