Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.2 Applications and Modeling with Linear Equations - 1.2 Exercises - Page 101: 20

Answer

$840$ miles.

Work Step by Step

Distance traveled in any of the two legs = (average speed)(time of travel). Going distance = $50x,$ Return distance = $55(32-x)$. Adding the times given in the table, we see that total time is 32 (x+32-x=32). We solve an equation obtained from (Going distance) = (Return distance) $50x=55(32-x)$ $50x=1760-55x$ $105x=1760$ $x=\displaystyle \frac{1769}{105}\approx 16.762$ Going distance = $50x\approx 50(16.762)=838.1\approx 840$ miles.
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