Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.2 Applications and Modeling with Linear Equations - 1.2 Exercises - Page 101: 19


$50$ miles.

Work Step by Step

Distance traveled =(average speed)(time of travel). Morning distance = $50x$. Afternoon distance = $40(x+\displaystyle \frac{1}{4})$. The equation we solve is obtained from: (Morning distance) = (Afternoon distance) $50x=40(x+\displaystyle \frac{1}{4})$ $50x=40x+10$ $10x=10$ $x=1$ (hour) So, the distance covered (in the morning) = $50x=50(1)=50$ miles.
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