## Precalculus (6th Edition)

Option $D$
With $x$=second number, then "six times a second number" = $6x$ "three less than six times a second number" = first number = $6x-3$ The sum of the two numbers is 46 so $(6x-3) + x = 46$ Therefore, the equation needed to solve the given problem is the one in Option $D$.