## Precalculus (6th Edition)

$a=8$ ft $b=14$ ft
The perimeter of a rectangle can be calculated as: $P=2a+2b$, where a and b are the width and the length of the rectangle. Here: $P=44$ ft $a+6=b$ By substituting, we get: $44=2a+2(a+6)$ $44=4a+12$ $32=4a$ $a=8$ ft $b=a+6=14$ ft