Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.9 - Linear Inequalities and Absolute Value Inequalities - Exercise Set - Page 139: 109


Range: $59^{\mathrm{o}}F $ to $95^{\mathrm{o}}F $, inclusive, or $[59^{\mathrm{o}}F,95^{\mathrm{o}}F].$

Work Step by Step

Given: $ 15\leq C\leq 35\qquad $ Replace C with the expression for F $ 15\displaystyle \leq\frac{5}{9}(F-32)\leq 35\qquad $ Solve for F. Begin by multiplying all parts with $\displaystyle \frac{9}{5}$ $15\displaystyle \cdot\frac{9}{5}\leq\frac{9}{5}\cdot\frac{5}{9}(F-32)\leq\frac{9}{5}\cdot 35$ $ 27\leq F-32\leq 63\qquad $ ... add 32 $59\leq F\leq 95$ Range: $\ \ 59^{\mathrm{o}}F $ to $95^{\mathrm{o}}F $, inclusive, or $[59^{\mathrm{o}}F,95^{\mathrm{o}}F].$
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