## Precalculus (6th Edition) Blitzer

$5$ years from 2014 is the year $2019$.
Let x be the number of years after 2014. 11.3 increased by $0.2x\quad=11.3+0.2x$ We want to find the x for which this equals $12.3.$ $11.3+0.2x=12.3 \qquad$ ... subtract $11.3$ $0.2x=12.3-11.3$ $0.5x=1.0 \qquad$ ... multiply with 5 $x=5$ $5$ years from 2014 is the year $2019$.