## Precalculus (6th Edition) Blitzer

Fill the blanks with: $x+5$, $4x+10$ $x^{2}+5x$
The length of a rectangle is 5 feet more than $x$ = $x+5.$ The perimeter equals 2$\times$(width + length) $=2(x+x+5)$ $=2(2x+5)=4x+10$ The area equals width $\times$ length = $x(x+5)=x^{2}+5x$