## Precalculus (6th Edition) Blitzer

$\dfrac{7}{6}$
The fractions are not similar because they have different denominators. Make the fractions similar by using their LCD of $6$ to obtain: $=\dfrac{1\cdot 3}{2 \cdot 3} + \dfrac{2\cdot 2}{3 \cdot 2} \\=\dfrac{3}{6}+\dfrac{4}{6}$ Add the numerators together to obtain: $=\dfrac{3+4}{6} \\=\dfrac{7}{6}$