Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set: 146

Answer

$\dfrac{7}{6}$

Work Step by Step

The fractions are not similar because they have different denominators. Make the fractions similar by using their LCD of $6$ to obtain: $=\dfrac{1\cdot 3}{2 \cdot 3} + \dfrac{2\cdot 2}{3 \cdot 2} \\=\dfrac{3}{6}+\dfrac{4}{6}$ Add the numerators together to obtain: $=\dfrac{3+4}{6} \\=\dfrac{7}{6}$
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