## Precalculus (6th Edition) Blitzer

distributive; $4x^5-8x^2+6$; $7x^3$
RECALL: For any real numbers a, b, c, and d, the distributive property states that $a(b+c+d) = ab + ac + ad.$ Thus, to simplify $7x^3(4x^5-8x^2+6)$, using the distributive property gives $7x^3(4x^5) -7x^3(8x^2) + 7x^3(6).$ Therefore, the missing expressions/words (in order) in the given statement are distributive; $4x^5-8x^2+6$; $7x^3.$