#### Answer

$A=C+D$

#### Work Step by Step

$b^A=MN$
$b^C=M$
$b^D=N$
$b^A=b^C\times b^D$
$b^A=b^{C+D}$
$A=C+D$

Published by
Pearson

ISBN 10:
0-13446-914-3

ISBN 13:
978-0-13446-914-0

$A=C+D$

$b^A=MN$
$b^C=M$
$b^D=N$
$b^A=b^C\times b^D$
$b^A=b^{C+D}$
$A=C+D$

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