Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.2 - Exponents and Scientific Notation - Exercise Set - Page 32: 142


False. $(7\times10^{5})+(2\times10^{-3})\gt9\times10^{2}$

Work Step by Step

$9\times10^{2}=900$ $(7\times10^{5})=700,000$ $(2\times10^{-3})=.002$ $(7\times10^{5})+(2\times10^{-3})=700000.002\ne900$
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