Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.6 - Conic Sections in Polar Coordinates - Exercise Set - Page 1032: 56


$(-3, 4)$ and $(4,-3)$

Work Step by Step

Step 1. From the first equation, we have $y=1-x$ Step 2. Substitute for $y$ in the second equation. We have $x^2+(1-x)^2=25$, $2x^2-2x-24=0$, or $x^2-x-12=0$ Step 3. Factoring the equation, we have $(x-4)(x+3)=0$, thus $x=-3, 4$ Step 4. We can find the solutions as $(-3, 4)$ and $(4,-3)$ Step 5. Check the solutions and they fit both equations.
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