Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.5 - Parametric Equations - Exercise Set - Page 1022: 97


The expression is $r=\frac{2}{1+\frac{\cos \theta }{2}}$

Work Step by Step

Let us consider the expression: $\frac{4}{2+\cos \theta }$ We divide the numerator and denominator by 2. $\begin{align} & \frac{4}{2+\cos \theta }=\frac{{4}/{2}\;}{{2+\cos \theta }/{2}\;} \\ & =\frac{2}{1+\frac{\cos \theta }{2}} \end{align}$ Thus, $r=\frac{2}{1+\frac{\cos \theta }{2}}$
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