## Precalculus (6th Edition) Blitzer

Step 1. From the given equation, we have $A=23, B=26\sqrt 3, C=-3$ Step 2. Evaluate $B^2-4AC=(26\sqrt 3)^2-4(23)(-3)=2028+276=2304$ Step 3. As $B^2-4AC\gt0$, the equation represents a hyperbola.