## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 9 - Section 9.2 - The Hyperbola - Exercise Set - Page 983: 69

#### Answer

See explanations.

#### Work Step by Step

From the equation, we have $a=3, b=1, c=\sqrt {a^2+b^2}=\sqrt {10}\approx3.16$. The center of the hyperbola is at $(0,0)$ and the transverse axis is horizontal. Thus, the foci can be located at $(\pm\sqrt {10},0)$

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