Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.2 - The Hyperbola - Concept and Vocabulary Check - Page 981: 10


$16$, $1$, $128$.

Work Step by Step

We can rewrite the equation as $9(x^2-8x+16)-16(y^2+2y+1)=16+9(16)-16$ which means that we need to add $16$ within the first parentheses to complete the square on $x$, and add $1$ to complete the square on $y$. The amount we need to add on the right side is $144-16=128$.
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