Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.2 - The Hyperbola - Concept and Vocabulary Check - Page 980: 3

Answer

$(0, -5)$, $(0, 5)$, $(0, -\sqrt {34})$, $(0, \sqrt {34})$.

Work Step by Step

From the given equation, we have $a^2=25, b^2=9$; thus $c=\sqrt {a^2+b^2}=\sqrt {34}$ with a vertical transverse axis. The vertices of the equation can be found at $(0, -5)$ and $(0, 5)$. The foci are located at $(0, -\sqrt {34})$ and $(0, \sqrt {34})$.
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