## Precalculus (6th Edition) Blitzer

a. $r=\frac{6}{1+cos\theta}$ b. $e=1$, $p=6$, parabola. c. See figure.
a. The equation, $r=\frac{6}{1+cos\theta}$, is already in the standard form of a conic in polar coordinates. b. From the above equation, we can determine $e=1$ and $ep=6$, which gives $p=6$. With $e=1$, the equation can be identified as a parabola. c. We can graph the polar equation as shown in the figure.