Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Cumulative Review Exercises - Page 1038: 6

Answer

$x=-1\pm\sqrt 2, \frac{2}{3}$
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Work Step by Step

Step 1. List the possible rational solutions as $\frac{p}{q}=\pm1,\pm2,\pm\frac{1}{3},\pm\frac{2}{3}$ Step 2. Using synthetic division to test solutions, we can find that $x=\frac{2}{3}$ is a zero as shown in the figure. Step 3. The quotient can be found as $3x^2+6x-3=3(x^2+2x-1)=0$, which gives $x=\frac{-2\pm\sqrt {8}}{2}=-1\pm\sqrt 2$ Step 4. The solutions are $x=-1\pm\sqrt 2, \frac{2}{3}$
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