## Precalculus (6th Edition) Blitzer

a. $\begin{bmatrix} 2400 & 2700 & 3000 \\ 2200 & 2500 & 2900 \\ 2000 & 2300 & 2600 \end{bmatrix}$ b. $\begin{bmatrix} 2000 & 2100 & 2400 \\ 1800 & 2000 & 2200 \\ 1600 & 1800 & 2100 \end{bmatrix}$ c. $\begin{bmatrix} 400 & 600 & 600 \\ 400 & 500 & 700 \\ 400 & 500 & 500 \end{bmatrix}$
a. Based on the given table, we have $M=\begin{bmatrix} 2400 & 2700 & 3000 \\ 2200 & 2500 & 2900 \\ 2000 & 2300 & 2600 \end{bmatrix}$ where the rows and columns are in agreement with the table. b. Similarly, we have $W=\begin{bmatrix} 2000 & 2100 & 2400 \\ 1800 & 2000 & 2200 \\ 1600 & 1800 & 2100 \end{bmatrix}$ c. We have $M-W=\begin{bmatrix} 2400 & 2700 & 3000 \\ 2200 & 2500 & 2900 \\ 2000 & 2300 & 2600 \end{bmatrix}-\begin{bmatrix} 2000 & 2100 & 2400 \\ 1800 & 2000 & 2200 \\ 1600 & 1800 & 2100 \end{bmatrix}=\begin{bmatrix} 400 & 600 & 600 \\ 400 & 500 & 700 \\ 400 & 500 & 500 \end{bmatrix}$ which represent the differences between men and women for the daily caloric needs based on various age groups and activity levels.