Answer
a. $\begin{bmatrix} 2400 & 2700 & 3000 \\ 2200 & 2500 & 2900 \\ 2000 & 2300 & 2600 \end{bmatrix}$
b. $\begin{bmatrix} 2000 & 2100 & 2400 \\ 1800 & 2000 & 2200 \\ 1600 & 1800 & 2100 \end{bmatrix}$
c. $\begin{bmatrix} 400 & 600 & 600 \\ 400 & 500 & 700 \\ 400 & 500 & 500 \end{bmatrix}$
Work Step by Step
a. Based on the given table, we have
$M=\begin{bmatrix} 2400 & 2700 & 3000 \\ 2200 & 2500 & 2900 \\ 2000 & 2300 & 2600 \end{bmatrix}$
where the rows and columns are in agreement with the table.
b. Similarly, we have
$W=\begin{bmatrix} 2000 & 2100 & 2400 \\ 1800 & 2000 & 2200 \\ 1600 & 1800 & 2100 \end{bmatrix}$
c. We have
$M-W=\begin{bmatrix} 2400 & 2700 & 3000 \\ 2200 & 2500 & 2900 \\ 2000 & 2300 & 2600 \end{bmatrix}-\begin{bmatrix} 2000 & 2100 & 2400 \\ 1800 & 2000 & 2200 \\ 1600 & 1800 & 2100 \end{bmatrix}=\begin{bmatrix} 400 & 600 & 600 \\ 400 & 500 & 700 \\ 400 & 500 & 500 \end{bmatrix}$
which represent the differences between men and women for the daily caloric needs based on various age groups and activity levels.
