Answer
The given statement is True.
Work Step by Step
Consider the matrix given below:
$A=\left[ \begin{matrix}
{{a}_{11}} & {{a}_{12}} \\
{{a}_{21}} & {{a}_{22}} \\
\end{matrix} \right]$
Then
$\begin{align}
& -4A=-4\left[ \begin{matrix}
{{a}_{11}} & {{a}_{12}} \\
{{a}_{21}} & {{a}_{22}} \\
\end{matrix} \right] \\
& =\left[ \begin{matrix}
-4{{a}_{11}} & -4{{a}_{12}} \\
-4{{a}_{21}} & -4{{a}_{22}} \\
\end{matrix} \right]
\end{align}$
We see that $-4A$ is obtained by multiplying each element of $A$ by $-4$.
Therefore, the given statement is true.
