Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 8 - Section 8.2 - Inconsistent and Dependent Systems and Their Applications - Exercise Set - Page 905: 53


The solution for the indicated problem is $8$.

Work Step by Step

Solve the given expression: Recall that $-\left( -a \right)=a$ $\begin{align} & \frac{1}{2}\left[ 8-\left( -8 \right) \right]=\frac{1}{2}\left[ 8+8 \right] \\ & =\frac{1}{2}\left[ 16 \right] \\ & =8 \end{align}$ Hence, the solution for the indicated problem is $8$.
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