#### Answer

The statement makes sense.

#### Work Step by Step

In an augmented matrix, any row can be deleted if every element of the row is zero.
Consider the following augmented matrix:
$\left[ \begin{matrix}
1 & -1 & -2 & 2 \\
0 & 1 & -10 & -1 \\
0 & 0 & 0 & 0 \\
\end{matrix} \right]$
The last row, that is, row 3 of the matrix, is expressed in the equation as:
$0x+0y+0z=0$
Since $0=0$, the above equation is true and it implies that the variable z can take any value.
Therefore, the system of linear equations has infinitely many solutions. Hence, row 3 of the above matrix can be deleted.