## Precalculus (6th Edition) Blitzer

$\left\{ 3-2z,\ 1-2z,\ z \right\}$
We start with: \begin{align} 3x-y+4z=8 & \\ y+2z=1 & \\ \end{align} Now converting it into an augmented matrix, we get, $\left[ \left. \begin{matrix} \begin{matrix} 3 & -1 & 4 \\ \end{matrix} \\ \begin{matrix} 0 & 1 & 2 \\ \end{matrix} \\ \end{matrix} \right|\begin{matrix} 8 \\ 1 \\ \end{matrix} \right]$ Further we will solve the equations for values of $x,y$ and $z$. \begin{align} & y=3-2z \\ & x=1-2z \\ & z=z \\ \end{align}