Answer
$\left\{ 3-2z,\ 1-2z,\ z \right\}$
Work Step by Step
We start with:
$\begin{align}
3x-y+4z=8 & \\
y+2z=1 & \\
\end{align}$
Now converting it into an augmented matrix, we get,
$\left[ \left. \begin{matrix}
\begin{matrix}
3 & -1 & 4 \\
\end{matrix} \\
\begin{matrix}
0 & 1 & 2 \\
\end{matrix} \\
\end{matrix} \right|\begin{matrix}
8 \\
1 \\
\end{matrix} \right]$
Further we will solve the equations for values of $ x,y $ and $ z $.
$\begin{align}
& y=3-2z \\
& x=1-2z \\
& z=z \\
\end{align}$
