## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 8 - Section 8.2 - Inconsistent and Dependent Systems and Their Applications - Concept and Vocabulary Check - Page 902: 1

#### Answer

The provided matrix has no solution.

#### Work Step by Step

In this matrix, it is impossible to convert the last matrix to the desired form of 1st down the main diagonal. Translating row 3 of the matrix into equation form, we get, $0x+0y+0z=-27$ There are no values of x, y and z for which $0=-27$ This is false, regardless of any values for x, y, z. Thus the last equation can never be a true statement and there is no solution.

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