## Precalculus (6th Edition) Blitzer

We know that it is stated that $\frac{A}{\left( x+2 \right)}+\frac{B}{\left( x-3 \right)}$ is the partial fraction decomposition of the algebraic expression $\frac{7x}{\left( x+2 \right)\left( x-3 \right)}$ into a series of smaller components. It is known that the partial fraction decomposition is the technique used for rational functions. It is the mathematical operation by which rational function can be expressed as a sum of a polynomial and several fractions, including ‘equating coefficients’. And the partial fraction decomposition associated with $\frac{px+q}{\left( x-a \right)\left( x-b \right)},a\ne b$, is as follows: $\frac{A}{\left( x-a \right)}+\frac{B}{\left( x-b \right)}$ Therefore, $\frac{A}{\left( x+2 \right)}+\frac{B}{\left( x-3 \right)}$ is the final simplified algebraic expression. Thus, the partial fraction decomposition of the expression, $\frac{7x}{\left( x+2 \right)\left( x-3 \right)}=\frac{A}{\left( x+2 \right)}+\frac{B}{\left( x-3 \right)}$ is correct.