Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.6 - Vectors - Exercise Set - Page 791: 2

Answer

a) The magnitude of the vector $u$ is equal to $2 \sqrt{13}$. b) The magnitude of the vector $v$ is equal to $2 \sqrt{13}$. c) Yes, $u=v$ Both vectors $u$ and $v$ have the same magnitude, that is, $2 \sqrt{13}$ and both are facing the same direction.

Work Step by Step

a) Here, $|u|=\sqrt{(-4-0)^2+(6-0)^2}=\sqrt {52}=2 \sqrt{13}$ This means that the magnitude of the vector $u$ is equal to $2 \sqrt{13}$. b) Here, $|v|=\sqrt{(-2-2)^2+(5-(-1))^2}=\sqrt {52}=2 \sqrt{13}$ This means that the magnitude of the vector $v$ is equal to $2 \sqrt{13}$. c) Yes, $u=v$ Both vectors $u$ and $v$ have the same magnitude, that is, $2 \sqrt{13}$ and both are facing the same direction.
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