## Precalculus (6th Edition) Blitzer

The magnitude of $\mathbf{u}$ is \begin{align} & \left\| \mathbf{u} \right\|=\sqrt{{{\left( 1-0 \right)}^{2}}+{{\left( 2-0 \right)}^{2}}} \\ & =\sqrt{1+4} \\ & =\sqrt{5} \end{align} The magnitude of $\mathbf{v}$ is \begin{align} & \left\| \mathbf{v} \right\|=\sqrt{{{\left( 3-2 \right)}^{2}}+{{\left( 2-0 \right)}^{2}}} \\ & =\sqrt{1+4} \\ & =\sqrt{5} \end{align} Both vectors have same magnitude and direction. Hence, $\mathbf{u}=\mathbf{v}$.