## Precalculus (6th Edition) Blitzer

The polar equation of the given polar curve is $r=1+\sin \theta$.
From the given polar curve, we can observe that it is heart-shaped or cardioid. Hence, $\frac{a}{b}=1$ And from the graph: For $\theta =\frac{\pi }{2}$ $r=2$ By applying the above condition, we can conclude that the polar equation for the graph will be $r=1+\sin \theta$.