Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.2 - The Law of Cosines - Exercise Set - Page 730: 40

Answer

$799.9\ mi$.
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Work Step by Step

Step 1. Draw a diagram as shown in the figure. Based on the given bearings and distances, we have $AB=580, BC=400\ mi$. Step 2. In triangle ABC, we have the angle $B=34^\circ+74^\circ=108^\circ$ Step 3. Using the Law of Cosines, let $AC=b$. We have $b^2=580^2+400^2-2(580)(400)cos(108^\circ)\approx639,784$ which gives $c\approx799.9\ mi$.
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