Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.1 - The Law of Sines - Exercise Set - Page 722: 53

Answer

The length of the toss is $\text{56}\text{.0 feet}$.

Work Step by Step

The length of the toss c is the distance from A to B. Using the law of sines we will find c: $\begin{align} & \frac{c}{\sin C}=\frac{b}{\sin B} \\ & \frac{c}{\sin 5.7{}^\circ }=\frac{562}{\sin 85.3{}^\circ } \\ & c=\frac{562\sin 5.7{}^\circ }{\sin 85.3{}^\circ } \\ & \approx 56.0 \end{align}$ Therefore, the length of the toss is $\text{56}\text{.0 feet}$.
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