Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.1 - The Law of Sines - Exercise Set - Page 721: 48

Answer

$27.0\ mi$ (from B) $33.5\ mi$ (from A)
1584370061

Work Step by Step

Step 1. Based on the given conditions, draw a diagram as shown in the figure (not to scale). Step 2. We can identify angle $A=90^\circ-48^\circ=42^\circ$, angle $B=90^\circ-34^\circ=56^\circ$, and angle $C=180^\circ-42^\circ-56^\circ=82^\circ$ Step 3. Using the Law of Sines, we have $\frac{sin42^\circ}{a}=\frac{sin82^\circ}{40}$, thus $a=\frac{40sin42^\circ}{sin82^\circ}\approx27.0\ mi$ Step 4. Similarly, we have $\frac{sin56^\circ}{b}=\frac{sin82^\circ}{40}$; thus $b=\frac{40sin56^\circ}{sin82^\circ}\approx33.5\ mi$
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