Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.1 - The Law of Sines - Exercise Set - Page 720: 24


There is no triangle with the provided measurements.

Work Step by Step

Using the ratio $\frac{a}{\sin A}$ or $\frac{10}{\sin 150{}^\circ }$ We will use the law of sines to find B. $\begin{align} & \frac{a}{\sin A}=\frac{b}{\sin B} \\ & \frac{10}{\sin 150{}^\circ }=\frac{30}{\sin B} \\ & \sin B=\frac{30\sin 150{}^\circ }{10} \\ & \sin B=1.5 \end{align}$ As we know that the sine can never exceed 1, therefore, there is no angle B for which $\sin B=1.5$.
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