Answer
There is no triangle with the provided measurements.
Work Step by Step
Using the ratio $\frac{a}{\sin A}$ or $\frac{10}{\sin 150{}^\circ }$
We will use the law of sines to find B.
$\begin{align}
& \frac{a}{\sin A}=\frac{b}{\sin B} \\
& \frac{10}{\sin 150{}^\circ }=\frac{30}{\sin B} \\
& \sin B=\frac{30\sin 150{}^\circ }{10} \\
& \sin B=1.5
\end{align}$
As we know that the sine can never exceed 1, therefore, there is no angle B for which $\sin B=1.5$.
