Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Section 5.5 - Trigonometric Equations - Exercise Set - Page 705: 154


The statement does not make sense.

Work Step by Step

We know that the equation is already in the form of an isolated trigonometric function on one side and a constant form on another side. Therefore, the value of $x$ can easily be found by using $\cos \pi =-1$ $\begin{align} & \cos \left( x-\frac{\pi }{3} \right)=\cos \pi \\ & x-\frac{\pi }{3}=\pi \\ & x=\pi +\frac{\pi }{3} \\ & x=\frac{4\pi }{3} \end{align}$ Thus, the equation can be simply solved by using the trigonometric identity. So, there is a need to apply the difference formula of $\cos $.
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