Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Section 5.5 - Trigonometric Equations - Exercise Set - Page 705: 154

Answer

The statement does not make sense.

Work Step by Step

We know that the equation is already in the form of an isolated trigonometric function on one side and a constant form on another side. Therefore, the value of $x$ can easily be found by using $\cos \pi =-1$ $\begin{align} & \cos \left( x-\frac{\pi }{3} \right)=\cos \pi \\ & x-\frac{\pi }{3}=\pi \\ & x=\pi +\frac{\pi }{3} \\ & x=\frac{4\pi }{3} \end{align}$ Thus, the equation can be simply solved by using the trigonometric identity. So, there is a need to apply the difference formula of $\cos $.
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