Answer
$$x=\frac{3\pi }{2}$$
Work Step by Step
We solve by factoring:
$$2\sin ^2x -4 \sin x -6=0 \quad \Rightarrow \quad (\sin x + 1)(\sin x - 3)=0 \quad \Rightarrow \quad \sin x +1=0 \quad \Rightarrow \quad \sin x= -1 \quad \Rightarrow \quad x= \frac{3\pi }{2}+2n \pi, \quad n \in \mathbb {Z}$$(Please note that the range of $\sin x$ is $[-1,1]$). So, $x=\frac{3\pi }{2}$ is the only solution in the interval $[0, 2\pi)$.
