Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Section 5.5 - Trigonometric Equations - Exercise Set - Page 703: 4


$\frac{\pi }{3}$ is not the solution of the given equation.

Work Step by Step

We know that according to the ratio table of trigonometry, the value of $\sin \frac{\pi }{3}$ is given as $\frac{\sqrt{3}}{2}$. $\begin{align} & \sin x=\frac{\sqrt{2}}{2} \\ & \sin \frac{\pi }{3}=\frac{\sqrt{2}}{2} \\ & \frac{\sqrt{3}}{2}=\frac{\sqrt{2}}{2} \end{align}$ Thus, $\sin x=\frac{\sqrt{2}}{2}$ is false.
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