Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Section 5.3 - Double-Angle, Power-Reducing, and Half-Angle Formulas - Concept and Vocabulary Check - Page 679: 11

Answer

The required solution is False.

Work Step by Step

The given statement shows that the formula for $\frac{\cos \,2A}{2}$ is cos A but there is no identity present for $\frac{\cos \,2A}{2}$ ; there is the identity for cos 2A that is as given below: $\cos \,2A={{\cos }^{2}}A-{{\sin }^{2}}A$ Or another identity is as follows: $\cos \,2A=2\,{{\cos }^{2}}A-1$ The given statement shows the wrong identity and formula.
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