Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Section 5.2 - Sum and Difference Formulas - Exercise Set - Page 672: 110

Answer

$\frac{1}{2}$ , $\frac{\sqrt{3}}{2}$ , $\frac{\sqrt{3}}{2}$ , and $\frac{1}{2}$.

Work Step by Step

By putting the values according to the trigonometric functions, we get: $\sin {{30}^{\circ }}=\frac{1}{2}$ $\cos {{30}^{\circ }}=\frac{\sqrt{3}}{2}$ $\sin {{60}^{\circ }}=\frac{\sqrt{3}}{2}$ $\cos {{60}^{\circ }}=\frac{1}{2}$
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