## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 5 - Section 5.2 - Sum and Difference Formulas - Exercise Set - Page 670: 72

#### Answer

The result of $\frac{\cos \left( \alpha -\beta \right)+\cos \left( \alpha +\beta \right)}{-\sin \left( \alpha -\beta \right)+\sin \left( \alpha +\beta \right)}$ is $\cot \beta$.

#### Work Step by Step

$\frac{\cos \left( \alpha -\beta \right)+\cos \left( \alpha +\beta \right)}{-\sin \left( \alpha -\beta \right)+\sin \left( \alpha +\beta \right)}$ by using the trigonometric identities, $\cos \left( \alpha +\beta \right)=\cos \alpha \cos \beta -\sin \alpha \sin \beta$ , $\cos \left( \alpha -\beta \right)=\cos \alpha \cos \beta +\sin \alpha \sin \beta$ $\sin \left( \alpha +\beta \right)=\sin \alpha \cos \beta +\cos \alpha \sin \beta$ , $\sin \left( \alpha -\beta \right)=\sin \alpha \cos \beta -\cos \alpha \sin \beta$ Now, the above expression can be further simplified as, \begin{align} & \frac{\cos \left( \alpha -\beta \right)+\cos \left( \alpha +\beta \right)}{-\sin \left( \alpha -\beta \right)+\sin \left( \alpha +\beta \right)}=\frac{\left( \cos \alpha \cos \beta +\sin \alpha \sin \beta \right)+\left( \cos \alpha \cos \beta -\sin \alpha \sin \beta \right)}{-\left( \sin \alpha \cos \beta -\cos \alpha \sin \beta \right)+\left( \sin \alpha \cos \beta +\cos \alpha \sin \beta \right)} \\ & =\frac{\cos \alpha \cos \beta +\sin \alpha \sin \beta +\cos \alpha \cos \beta -\sin \alpha \sin \beta }{-\sin \alpha \cos \beta +\cos \alpha \sin \beta +\sin \alpha \cos \beta +\cos \alpha \sin \beta } \\ & =\frac{\cos \alpha \cos \beta +\cos \alpha \cos \beta }{\cos \alpha \sin \beta +\cos \alpha \sin \beta } \\ & =\frac{2\cos \alpha \cos \beta }{2\cos \alpha \sin \beta } \end{align} Use, $\frac{\cos x}{\sin x}=\cot x$ \begin{align} & \frac{2\cos \alpha \cos \beta }{2\cos \alpha \sin \beta }=\frac{\cos \beta }{\sin \beta } \\ & =\cot \beta \end{align} Thus, $\frac{\cos \left( \alpha -\beta \right)+\cos \left( \alpha +\beta \right)}{-\sin \left( \alpha -\beta \right)+\sin \left( \alpha +\beta \right)}$ can be simplified as $\cot \beta$. Hence, the result of $\frac{\cos \left( \alpha -\beta \right)+\cos \left( \alpha +\beta \right)}{-\sin \left( \alpha -\beta \right)+\sin \left( \alpha +\beta \right)}$ is $\cot \beta$.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.