Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Section 5.2 - Sum and Difference Formulas - Concept and Vocabulary Check - Page 668: 4

Answer

Identity for $\sin \left( C-D \right)$ is expressed as $\sin C\cos D-\cos C\sin D$.

Work Step by Step

From the difference formula of sines, the sine of the difference between two angles, say A and B, is expressed as, $\sin \left( A-B \right)=\sin A\cos B-\cos A\sin B$ Thus, for angles C and D, $\sin \left( C-D \right)=\sin C\cos D-\cos C\sin D$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.