Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Review Exercises - Page 709: 64


$3.7890, 5.6358$

Work Step by Step

Step 1. Find the reference angle as $x=sin^{-1}(0.6031)\approx0.6474$ Step 2. For $sin(x)=-0.6031$, we have solutions in $[0,2\pi)$ as $x=\pi+0.6074\approx3.7890$ and $x=2\pi-0.6074\approx5.6358$ Step 3. Thus, we have all the solutions in $[0,2\pi)$ as $x=3.7890, 5.6358$
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