Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Mid-Chapter Check Point - Page 684: 15


Please see below.

Work Step by Step

We verify as follows: $$\tan (\alpha + \beta)\tan (\alpha - \ beta )=\frac{\tan \alpha + \tan \beta }{1-\tan \alpha \tan \beta} \frac{\tan \alpha - \tan \beta }{1+\tan \alpha \tan \beta}=\frac{\tan ^2 \alpha - \tan ^2 \beta }{1-\tan ^2 \alpha \tan ^2 \beta}$$
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