Answer
$$x=-17$$
Work Step by Step
We solve as follows:
$$8^{x+5}=4^{x-1} \quad \Rightarrow \quad (2^3)^{x+5}=(2^2)^{x-1} \quad \Rightarrow \quad 2^{3x+15}=2^{2x-2} \quad \Rightarrow \quad 3x+15=2x-2 \quad \Rightarrow \quad x=-17$$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Section 4.5 - Graphs of Sine and Cosine Functions - Exercise Set - Page 599: 121
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