## Precalculus (6th Edition) Blitzer

We know that a sine function of the form $y=A \sin (Bx-C)$ has phase shift $\frac{C}{B}$. The graph of $y=A \sin (Bx-C)$ is the graph of $y=A\sin Bx$ horizontally shifted $\frac{C}{B}$ units to the right (if $\frac{C}{B} \gt 0$) or to the left (if $\frac{C}{B} \lt 0$).